18x^2-168x+294=0

Solution for 18x^2-168x+294=0 equation:

18x^2-168x+294=0

a = 18; b = -168; c = +294;
Δ = b2-4ac
Δ = -1682-4·18·294
Δ = 7056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7056}=84$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-168)-84}{2*18}=\frac{84}{36}
=2+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-168)+84}{2*18}=\frac{252}{36}
=7
$